As its name implies, this unit shows us the distance (in meters) traveled by an object during a second. Meter per Second is a unit consisting of the standard unit of length, the meter, with the standard unit of time, the second. This does not obviously mean that the car has constantly shifted at this speed, there may be parts of the route on which it has been faster and parts where it has circulated more slowly. This measure is usually an average, that is, if a car traveled the distance of 210 km between two cities and to take this route, it took an hour and a half, so we will get a speed of 140 kilometers per hour (140 km/h). As its name implies, this unit represents the distance (in kilometers) traveled by an object for one hour. In these countries, road speed limits are calculated in kilometers per hour, which is abbreviated as kph or km/h. (266.Kilometer per hour is a measure of speed, typically used in countries that use the metric system. How much further will the train move before coming to rest? (Assuming the retardation to be constant). The maximum initial velocity of the ball = V i =?Ģ.9 When brakes are applied, the speed of a train decreases from 96 kmh-1 to 48 kmh-1 in 800 m.Maximum height reached by the ball S = h =?.Velocity at maximum height = V f = 0 ms -1 Time to reach maximum height (one sided time) = t = 6/2 = 3 s Solution: Acceleration due to gravity = g = -10 ms -1 (for upward motion) Calculate (i) Maximum height reached by the ball (ii) initial velocity of the ball (45m, 30 ms-1) Find the total distance travelled by train.įinal velocity = V f = 48 kmh -1 = 48 x 1000/3600 = 13.333 ms -1Ģ.8 A cricket ball is hit vertically upwards and returns to ground 6 s later. Finally, it moves with uniform retardation and is stopped after 3 minutes. (36 kmh -1)Ģ.7 A train starting from rest, accelerates uniformly and attains a velocity of 48 kmh -1 in 2 minutes. Find its speed in kmh-1, when it has moved through 100 m. Solution: Initial velocity = Vi = 40 ms -1Ģ.6 A train starts from rest with an acceleration of 0.5 ms -2. It comes to rest in the next 10 s with uniform deceleration. Total time = time to reach maximum height + time to return to the groundĢ.5 A car moves with a uniform velocity of 40 ms -1 for 5 s. (I) Maximum height attained by the ball S =?
Solution: Initial velocity = V i = 30 ms -1Īcceleration due to gravity g = -10 ms -2 How long it will take to return to the ground? (45 m, 6 s) Calculate the maximum height reached by the ball. Solution: Initial velocity = V i = 10 ms -1Ģ.4 A tennis ball is hit vertically upward with a velocity of 30 ms -1, it takes 3 s to reach the highest point. Find the distance travelled during this time and the final velocity of the car.
It accelerates at 0.2 ms -2 for half minute. What will be its speed at the end of 100 s.? (20 ms -1)Ģ.3 A car has a velocity of 10 ms -1. It moves through 1 km in 100 s with uniform acceleration. (80 s)Ģ.1 A train moves with a uniform velocity of 36 kmh-1 for 10 s. 2.10 In the above problem, find the time taken by the train to stop after the application of brakes.2.9 When brakes are applied, the speed of a train decreases from 96 kmh-1 to 48 kmh-1 in 800 m.(ii) initial velocity of the ball (45m, 30 ms-1).2.8 A cricket ball is hit vertically upwards and returns to ground 6 s later.Find the total distance travelled by train. 2.7 A train starting from rest, accelerates uniformly and attains a velocity of 48 kmh-1 in 2 minutes.2.6 A train starts from rest with an acceleration of 0.5 ms-2.
2.5 A car moves with a uniform velocity of 40 ms-1 for 5 s.2.4 A tennis ball is hit vertically upward with a velocity of 30 ms-1, it takes 3 s to reach the highest point.It accelerates at 0.2 ms-2 for half minute. What will be its speed at the end of 100 s.? (20 ms-1) 2.1 A train moves with a uniform velocity of 36 kmh-1 for 10 s.
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